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The integer v is greater than 1. If v is the square of an integer, which of the following numbers must also be the square of an integer?

Indicate all such numbers.
a + $$\frac{1}{a}$$= $$\sqrt{5}$$

Quantity A

$$a^{2}$$+$$(\frac{1}{a})^{2}$$

Quantity B

3


(x+$$\frac{1}{x}$$)=$$\sqrt{5}$$

Quantity A

$$x^{2}$$+$$\frac{1}{x^{2}}$$

Quantity B

3


$$\frac{0.99999999}{1.0001}$$ - $$\frac{0.99999991}{1.0003}$$ = ?

Quantity A

$$x^{2}$$+1

Quantity B

2x-1


xy+y < 0

Quantity A

x

Quantity B

y


Quantity A

$$(2m+1)^{2}$$

Quantity B

$$(2(m+1))^{2}$$


$$x^{2}$$-$$y^{2}$$=-10

Quantity A

x+y

Quantity B

x-y


x is a negative integer

Quantity A

$$(2^x)^2$$

Quantity B

$$(x^2)^x$$


n is a positive integer

Quantity A: $$(\frac{1}{2})^{n}$$

Quantity B: (3)·$$(\frac{1}{10})^{n}$$

Quantity A

$$\frac{x}{(x+1)}$$

Quantity B

1


If n=$$2^{3}$$, then$$n^{n}$$=
s and t are positive integers, and $$32^{s}$$=$$2^{t}$$.

Quantity A

s:t

Quantity B

0.2


If a, b, x, and y are positive integers, and $$13^{a}$$*$$13^{b}$$=($$13^{x})^{y}$$=$$13^{13}$$, what is the average (arithmetic mean) of a, b, x, and y?

Give your answer as a decimal.
Which of the following is/are equal to $$\frac{1}{560}^{-4}$$?

Indicate all correct answers.
$$a_1$$=1, $$a_2$$=1, $$a_n$$=0.2$$a_{n-1}$$(n ≥ 3)

Quantity A: $$a_6$$

Quantity B: $$25^{3}$$$$0.2^{10}$$
Which of the following is equal to (6)($$14^{8}$$)+(15)($$14^{7}$$)?
$$x^{y}$$ > 0, x$$y^{2}$$ < 0

Quantity A

x

Quantity B

y


x is an integer greater than 1.

Quantity A

$$3^{x+1}$$

Quantity B

$$4^{x}$$


0 < a< b < 1 < c < d, c and d are both integers

Quantity A

$$a^{c-d}$$

Quantity B

$$b^{d-c}$$


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