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The volume V of the frustum of a right circular cone is given by V=($$\frac{πh}{3}$$)($$R^{2}$$+Rr+$$r^{2}$$), where h is the height of the frustum, R is the radius of its lower base, and r is the radius of its upper base, as shown. If the volume of the frustum of a right circular cone is 148π, its height is 12, and the radius of its upper base is 3, what is the radius of the lower base of the frustum?
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以上解析由 考满分老师提供。