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On her walk today, Emma walked along a straight path between the entrance to her house, H, and the entrance to library, L, passing a crosswalk sign, J, and then a crosswalk sign, K. First Emma walked from H to J and then turned around and walked back from J to H. Then she walked directly from H to L, stopping briefly at J and K on her way. The total distance that Emma walked from H to J and back from J to H was $$\frac{2}{9}$$ of the distance that she walked directly from H to K and $$\frac{1}{6}$$ of the distance that she walked directly from H to L. If Emma walked a total of 420 meters during her walk today. what was the distance, in meters, that she walked from K to L?
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· 相关考点
3.3.3 解多元一次方程组与相关应用题
3.3.3 解多元一次方程组与相关应用题
以上解析由 考满分老师提供。
